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Figure 1-15.DeForest's experiment.
INTRODUCTION TO GRID BIAS

Neets Module 06-Introduction to Electronic Emission, Tubes, and Power Supplies
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1-21 was a variation in plate current of 7.5 milliamperes. Instead of amplification, De Forest had obtained "conversion," or in other words, converted a signal voltage to a current variation. This wasn’t exactly what he had in mind. As it stood, the circuit wasn’t very useful. Obviously, something was needed. After examining the circuit, De Forest discovered the answer—Ohm's law. Remember E = I × R? De Forest wanted a voltage change, not a current change. The answer was simple: In other words, run the plate current variation (caused by the voltage on the grid) through a resistor, and cause a varying voltage drop across the resistor. This is shown in figure 1-16. Figure 1-16.—Operation of the plate load resistor. The circuit is identical to the one in figure 1-15 except that now a resistor (called a plate-load resistor, RL) has been added to the plate circuit, and a voltmeter has been added to measure the voltage drop across RL. In view (A) of figure 1-16, the control grid is at 0 volts. Once again 5 milliamperes flow in the plate circuit. Now, the 5 milliamperes must flow through RL. The voltage drop is equal to: E = I × R E = (5 × 10-3 amperes) × (10 × 103 ohms) E = (5 × 10-3) × (10 × 10 3) E = 5 × 10 E = 50 volts Thus the voltage drop across the plate-load resistor, RL, is 50 volts when no voltage is applied to the grid. In view (B) of the figure, +3 volts is applied to the control grid. Once again plate current increases to 10 milliamperes. The voltage drop across RL  is






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